AABC with vertices A(-4, 3), B(-2,-1) and C(-1, 3) is translated by 3 units right and 2 units up, then it is rotated 90° counterclockwise about the origin. The new image of the triangle is represented by
ABC
What are the coordinates of A'?

Answer :

A. (0,-2)

B. (-5,-1)

C. (-5,1)

D (5,0)

C

Step-by-step explanation:

(-4, 3) 3 units right = +3x = -1

(-1, 3) 2 units up = +2y = 5

(1, 5) A rotation of 90° counterclockwise around the origin can be described in mathematical terms as (x, y) → (−y, x).

(1, 5) → (-5, 1), or C

B. (-5, -1)

Step-by-step explanation:

Since we're solving for A :

A (-4, 3) translated 3 units to the right and 2 units up would be A (-4 + 3, 3 + 2), which is A' (-1, 5). Then, we have to rotate it 90 degrees clockwise. This would be (-5, -1), as the formula states (x, y) -> (-y, x), which means the x stays the same but goes to the 'y' position, and the y sign changes and goes to the 'x' position.

So, it would be (-5, -1) :)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2