Advanced Trigonometry please help

i) Area = 25 m²

ii) slope of roof = 36.87°

Step-by-step explanation:

(i)  Let the midpoint of AB = M

Find BC by using Pythagoras' Theorem:  a² + b² = c²

(where a and b are the legs, and c is the hypotenuse of a right triangle)

Legs = MB and MC, hypotenuse = BC

⇒ 1.5² + 2² = BC²

⇒ 6.25 = BC²

⇒ BC = √(6.25) = 2.5

Area of a rectangle = width x length = BC x BE

⇒ area of BCFE = 2.5 x 5 = 12.5

⇒ area of ACFD = area of BCFE = 12.5

Therefore area covered by tiles = 12.5 + 12.5 = 25 m²

ii)

The angle of the slope of the roof will be angle ∠B of the right triangle ΔCMB.

Using sin(A)/a = sin(B)/b = sin(C)/c

sin(90)/2.5 = sin(B)/1.5

0.4 = sin(B)/1.5

0.6 = sin(B)

∠B = 36.87°

step-by-step explanation:

do you have a copy of the table?

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i