What value of g makes the equation true?

(x+7)(x-4)=x²+gx-28

g = 3

Step-by-step explanation:

(x+7)(x-4) = x²+ gx -28

Multiply the two parenthesis

(x+7)(x-4)= x² -4x +7x -28

Combine like terms

(x+7)(x-4)= x²+3x-28

Compare the equations

x²+ gx -28 =  x² +3x -28

g = 3

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?