Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

0.8

Step-by-step explanation:

1. Subtract both equations

2. You will get your answer

(Hope I'm right)

Results

The percent error between 75 and 80 is 6.667%

Solution:

Given: Accepted Value = 75 , Observed Value = 80

Percent Error Formula

Percent Error = | (Observed Value − Accepted Value) / Accepted Value | × 100  

Substitute values into the formula and solve:

Percent Error = | (80 − 75) / 75 | × 100  

= | (5) / 75 | × 100  

= | 0.067 | × 100  

= 6.667% (three decimal places)

Percent Error = 6.667%

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what "following statement"?

step-by-step explanation:

%40

step-by-step explanation: