Given the initial amounts listed, what is the limiting reagent, and how much of the other reactant is in excess? P4O6(s)+6H2O(ℓ)→4H3PO4
P4O6: 35.6 g 6H2O: 4.77 g

three-fourths of an hour

36÷48=0.75

0.75=

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

answer: what are the following choices

i need a diagram

step-by-step explanation:

no