in the sketch below, the coordinates of the vertices of triangle ABC are A(2:1), B(-2:-3) and C(-4:3) with D(-1: 2) on AC and E(-3;0) on BC. C4.3) 0-1:2 E 3.0) 1-2-3 1.1 Calculate the gradients of AB and DE. 1.2 What can you deduce about lines AB and DE? Give a reason for your answer.

  1.1  gradients of both AB and DE are 1

  1.2  the lines are parallel

Step-by-step explanation:

You can see from the graph, that both segment AB and segment DE have a rise of 1 unit for each run of one unit. The slope is the ratio of rise to run, so is 1/1 = 1.

The slope of each segment is 1.

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Lines with the same slope are parallel.

 Lines AB and DE are parallel.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

283 square feet

step-by-step explanation:

good luck