Square DEFG is inscribed in equilateral triangle ABC with a side length of 3+2√3. Find: area of the square

9 units²

Step-by-step explanation:

**Refer to the attached diagram**

The angles in the right triangle FAD (and HBE) are 30-60-90 which means that its sides will be in the ratio 1 : √3 : 2

Let x = the smallest side

Therefore, the sides of the right triangle FAD are in the ratio  x : √3x : 2x

This means that:

We are told that the side length of the triangle is 3 + 2√3, so:

As the side length of the square is √3x,  and x = √3,

⇒ side length of the square = √3 x √3 = 3

Now we know the side length of the square, we can calculate the area:

⇒ area of a square = side length x side length = 3 x 3 = 9 units²

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube