This table shows values that represent a quadratic function, х
0
1
2
3
چي د
y
-1
2
5
-10
-17
-26
37
4
5
6
What is the average rate of change for this quadratic function for the interval
from x = 4 to x = 6?

umumumumum

im not sure

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

i believe a. 12x≥120 is the answer

where is the graph, sweetheart?

step-by-step explanation: