write an equation of a line passing through the point (-4,11) and perpendicular to the line 4x + 5y = -45

y = 5/4x - 6

Step-by-step explanation:

First, put 4x + 5y= -45 in y = mx + b form

4x + 5y= -45

5y = -4x - 45

y = -4/5x - 9

So, the slope is -4/5. Perpendicular lines have a opposite reciprocal slope, so the line's slope will be 5/4 right so to find the equation of the perpendicular line in this question, plug in the slope and given point into y = mx + b, and solve for b

y = mx + b

-11 = 5/4(-4) + b

-11 = -5 + b

-6 = b

so you should Plug in b and the slope into y = mx + b

y = 5/4x - 6

So, the equation is y = 5/4x - 6

if this doesn't make sense i don't know what will

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

560

step-by-step explanation:

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