Sorry if it's a bother, but what's the answer to these? I'm having a little bit of trouble.

~Let's change 9.9² to 10² since we have to estimate.~

We know that:

Solving the expression:

The estimated value of 9.9² × 1.79 is 179.

~Let's change √97.5 to √100 and 1.96 to 2 since we have to estimate.~

We know that:

Solving the expression:

The estimated value of √97.5 ÷ 1.96 is 5.

answer: 12   they all have at least 28 days

step-by-step explanation: haha

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages