Tracy wants to determine the coordinates of the minimum value of a quadratic function. She writes the equation for the function in different forms.
Which form of the function would be MOST helpful to determine the coordinates of the
minimum value? *

O y = (x + 1)2 - 25
O y = x² + 2x - 24
O y = 2(x - 12) + x?
O y = (x - 4) (x + 6)

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.