Please help its due today 21 points

Step-by-step explanation:

A parallelogram is basically a shape with 4 corner and/or sides that has 2 sides that are 'parallel', as stated in the name itself.

D.) Square MARK ME BRAINLIEST!!

Step-by-step explanation:

A quadrilateral is a rectangle if and only if it has four right (congruent) angles. ABCD is a rectangle if and only if ∠A≅∠B≅∠C≅∠D.A quadrilateral is a rhombus if and only if it has four congruent sides. ABCD is a rhombus if and only if AB⎯⎯⎯⎯⎯⎯⎯≅BC⎯⎯⎯⎯⎯⎯⎯⎯≅CD⎯⎯⎯⎯⎯⎯⎯⎯≅AD⎯⎯⎯⎯⎯⎯⎯⎯.A quadrilateral is a square if and only if it has four right angles and four congruent sides. By definition, a square is a rectangle and a rhombus. ABCD is a square if and only if ∠A≅∠B≅∠C≅∠D and AB⎯⎯⎯⎯⎯⎯⎯≅BC⎯⎯⎯⎯⎯⎯⎯⎯≅CD⎯⎯⎯⎯⎯⎯⎯⎯≅AD⎯⎯⎯⎯⎯⎯⎯⎯.You can always show that a parallelogram is a rectangle, rhombus, or square by using the definitions of these shapes. There are some additional ways to prove parallelograms are rectangles and rhombuses, shown below:1.  A parallelogram is a rectangle if the diagonals are congruent. ABCD is parallelogram. If AC⎯⎯⎯⎯⎯⎯⎯⎯≅BD⎯⎯⎯⎯⎯⎯⎯⎯, then ABCD is also a rectangle.2.  A parallelogram is a rhombus if the diagonals are perpendicular. ABCD is a parallelogram. If AC⎯⎯⎯⎯⎯⎯⎯⎯⊥BD⎯⎯⎯⎯⎯⎯⎯⎯, then ABCD is also a rhombus.3.  A parallelogram is a rhombus if the diagonals bisect each angle. ABCD is a parallelogram. If AC⎯⎯⎯⎯⎯⎯⎯⎯ bisects ∠BAD and ∠BCD and BD⎯⎯⎯⎯⎯⎯⎯⎯ bisects ∠ABC and ∠ADC, then ABCD is also a rhombus.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the answer for your question is

step-by-step explanation: