**A mass m2 = 1.5 kg is initially moving with velocity vo. It collides completely inelastically with a block of mass m2 = 2.0 kg. The second block is attached to a spring with a spring constant of k = 5.6x10ʻN/m. The
block and spring lie on a frictionless horizontal surface. The spring compresses a distance of 0.20 m upon
collision
(a) What is the velocity of the mass mi and the block immediately after the collision?
(b) What is the initial velocity of the mass mi immediately before the collision?
(C) If the block were attached to a long string and hung as a pendulum, how high would the block and mass
mi rise after the collision?

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.