Question 4 (Essay Worth 10 points) (04.03 MC)
Find the area of the following shape. You must show all work to receive credit.

12 sq. units

Step-by-step explanation:

Because this is an irregular polygon, we can break the figure into simpler shapes and add the areas together.  

For the left triangle, use the formula (b × h)

(2 × 2)

(4) = 2 sq. units

For the top triangle:

(4 × 2)

(8) = 4 sq. units

For the middle rectangle, use the formula b × h

(3 × 2) = 6 sq. units

Now add together all the areas.

2 qu. units + 4 sq. units + 6 sq. units = 12 sq. units

Hope this helps~!

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)