F(x) = 2x - 3 and g(x) = x - 1.
Find f((g(x)) - g(f(2))

(f + g)(x) = I2x + 1I + 1 ⇒ C

Step-by-step explanation:

∵ f(x) = I2x + 1I + 3

∵ g(x) = -2

→ We need to find (f + g)(x), which means add the two functions

∵ (f + g)(x) = f(x) + g(x)

→ Substitute the right side of each function on the right side

∴ (f + g)(x) = I2x + 1l + 3 + (-2)

→ Remember (+)(-) = (-)

∴ (f + g)(x) = I2x + 1I + 3 - 2

→ Add the like terms in the right side

∵ (f + g)(x) = I2x + 1I + (3 - 2)

∴ (f + g)(x) = I2x + 1I + 1

i hope this work for you

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