Rebecca wants to prove that if the diagonals in a parallelogram are perpendicular, then it is a rhombus. B
А
с
D
Select the appropriate rephrased statement for rebecca's proof.
Choose 1
In quadrilateral ABCD, AB DC and AD BC, then AC 1 BD and
AB = BC = CD= DA
In quadrilateral ABCD, AC 1 BD and AB = BC = CD=D. A then AB | DC
and AD BC.
In quadrilateral ABCD FAB DC. AD BC, and AC 1 BD. then
1
AB= BC = CD = D. A.
In quadrilateral ABCD. it AB = BC = CD= D. A. then AB DC, AD BC, and
AC1BD

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

40 minutes

step-by-step explanation:

add the time and multiply by 2

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step-by-step explanation: