Guys, I’m giving you at least 100 points for you to answer to my last week of my math and geometric word problem homework paper from The Hung Vuong Learning Centre Incorporated! So guys, please listen up and pay attention to me without ignoring my last month’s math and geometric word problem homework paper from The Hung Vuong Learning Centre Incorporated for no reason! :D There are 3 remaining math word problem questions that you need to answer in order for you to get a Brainliest award if your answers are the best with the best efforts and explanations.

The question #10 is break 75 down into 2 parts so that the larger part is 13 more than the smaller.

The question #11 is there are 4 numbers, the first is 20 less than the second, the third is 1 more than twice the first and the fourth is 4 more than the second. We also know that the sum of the first and second equals the sum of the third and fourth numbers. Please help me in order to find the numbers.

The question #12 is one quarter of a number is being increased by one half of the same number is 12. Please help me in order to find a number.

Please answer to my math word problem question as soon as possible with the best efforts and the best step-by-step explanations in order to get the Brainliest award of all the time! :D

Well anyways, guys, good luck on answering 3 remaining of my math and geometric word problem questions of my last week math and geometric word problem homework paper from The Hung Vuong Learning Centre Incorporated in order to get the best Brainliest award of all of the time, and I will check the answers to see if it’s appropriate for me. :)

Q11:  31 and 44

Q12: -5, 15, -9, 19

Q13: 16

Step-by-step explanation:

Question 10

Let x = smaller part

Let y = larger part

Given sum of parts is 75:

x + y = 75

Given the larger part is 13 more than the smaller part:

y = 13 + x

Substitute y = 13 + x into x + y = 75 and solve for x:

⇒ x + 13 + x = 75

⇒ 2x + 13 = 75

⇒ 2x = 62

⇒ x = 31

Substitute found value of x into y = 13 + x and solve for y:

⇒ y = 13 + 31

⇒ y = 44

Therefore, the smaller part is 31 and the larger part is 44

Question 11

Let x = first number

Let y = second number

Let z = third number

Let w = fourth number

Given the first is 20 less than the second:

x = y - 20

⇒ y = x + 20

Given the third is 1 more than twice the first:

z = 2x + 1

Given the fourth is 4 more than the second:

w = y + 4

Given the sum of the first and second equals the sum of the third and fourth numbers:

x + y = z + w

Substitute the first 3 equations into x + y = z + w  and rearrange to make y the subject:

⇒ (y - 20) + y = (2x + 1) + (y + 4)

⇒ 2y - 20 = 2x + y + 5

⇒ y = 2x + 25

Rearrange x = y - 20 to make y the subject:

x = y - 20

⇒ y = x + 20

Now equate the equations and solve for x:

⇒ x + 25 = 20

⇒ x = -5

Now we have found the value of x, substitute into z = 2x + 1 to find z:

⇒ z = 2(-5)+ 1

⇒ z = -9

and substitute the value of x into y = x + 20 to find y:

⇒ y = -5 + 20

⇒ y = 15

finally substitute the value of y into w = y + 4 to find w:

⇒ w = 15 + 4

⇒ w = 19

Therefore,

Question 12

Let x = unknown number

Given one quarter of a number is being increased by one half of the same number is 12:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;