Given: ABCD is a rectangle. Prove: ΔABC is congruent to ΔCDA ABDC is a rectangle.
ABCD is a parallelogram. AB is congruent to DC and BC is congruent to DA AC is congruent to AC ΔABC is congruent to ΔCDA Given Definition of a rectangle. Opposite sides of a parallelogram are congruent. _ _
A. Symmetric Property of congruent; SAS
B. Reflexive Property of congruent to; SAS
C. Symmetric Property of congruent; SSS
D. Reflexive Property of congruent; SSS

D

3. Reflexive Property of (Congruence) ≅

4. SSS (Side to Side to Side Congruence rule)

Step-by-step explanation:

this is D reflexive property of SSS

3. Any geometric figure compared to itself is congruent to itself so this is why:

4. Since we have a parallelogram, therefore we can say:

Both triangles ABC and CDA satisfy the side to side to side congruence, since their 3 sides are congruent.

So, It's D.

P.S.

Notice that the angle measure information is not included in the data above that's why we cannot say it is SAS congruence.

sadsdda

step-by-step explanation: