a bag contains 11 counters, five of the counters are white .a counter is taken out of the bag at random and not replaced. a second counter is taken out of the bag at random. calculate the probability that only one of the counters are white

6/11

Step-by-step explanation:

5 of the counters are white that are taken out of the bag. That means if one more was taken out if the bag after that was the only white counter left then we can conclude that since there are 11 counters in the bag and 6 are white then, the probability of picking a white counter would be 6/11.

Have a great rest of your day
#TheWizzer

P(of picking one of the white counters )= 8/11

Step-by-step explanation:

Firstly you need to identify the counters

White counters = 5

Unknown= 6

Total outcome = 11

With the aid of a tree diagram and following the condition of not replaced we go on and compute our findings

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.

lol we need to see what the question is asking about

step-by-step explanation: