A fair coin is tossed 3 consecutive times. What is the probability that the result of the first toss is heads and the results of the next two are tails? A: 1/8
B: 1/6
C: 1/2
D: 1/4

a). 1/8

Step-by-step explanation:

If the coin is fair, then the odds of getting heads or tails should be equal, 12.

Then 3 tosses of tails will have a chance of 12⋅12⋅12=18.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.