Amelie spins the following spinner, which has 10 equally sized spaces numbered 1 through 10. The numbers 1 and 7 are colored blue; the numbers 2, 4, and 6 are red; and the numbers 3, 5, 8, 9, and 10 are green. What is the probability that Amelie spins either an odd number or a red number?

Enter your answer as a reduced fraction, like this: 3/14

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Step-by-step explanation:

The spinner has 10 equally sized spaces.

Numbers 1 and 7 are colored blue.

Numbers 2, 4, and 6 are red.

Numbers 3, 5, 8, 9, and 10 are green.

There are three numbers or sections in the spinner are red. That means the probability of getting a red is 3/10. This fraction cannot be reduced nor simplified.

There are five sections that are odd numbers. Those are 1, 3, 5, 7, and 9. The probability of getting a odd number is 5/10. Unlike the fraction 3/10, 5/10 can be simplified. It can be reduced to 1/2.

Combined, the probability of getting both red and odd sections are 7/10. This fraction cannot be simplified.

(c, 0) i might be wrong so don't put full faith on my answer

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05