What is the sum of the solutions to the equation below? 8x^2 + 2x - 3 = 0
A) 3/8 B) 1/4 C) -1/4 D - 3/8

(x−1)43x3−8x2+10 can be resolved into partial fraction as x−1A+(x−1)2B+(x−1)3C+(x−1)4D

So , 3x3−8x2+10=A(x−1)3+B(x−1)2+C(x−1)+D

Put x=1 , we get 3−8+10=D

D=5

Comparing the coefficient of x3 on both sides we get , A=3 .

So equation reduces to 3x3−8x2+10=3(x−1)3+B(x−1)2+C(x−1)+5

Now compare the constant on both sides , 10=−3+B−C+5

=>8=B−C - (1)

Comparing the coefficent of x2 we get −8=−9+B

=>B=1

So , put B=1 in (1) , we get C=−7

Therefore , (x−1)43x3−8x2+10=x−13+(x−1)21−(x−1)37+(x−1)45

Step-by-step explanation:

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