A substance requires 310 J of heat to raise the temperature from 19 °C to 42 °C.. If the mass of the substance is 20 g, what is the specific
heat of the substance?

.674  j / (g-C)

Step-by-step explanation:

Spec heat = heat required to raise 1 gram of substance 1 degree celsius

       Spec heat units : j / (gm-C)

s     310 j / (20g * (42-19)C  = .674

ce pula mea vrei ma

step-by-step explanation:

gayule

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

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