How to find three consecutive odd numbers whose product is 2145?

Hello : 
2145 = 11×13×3×5 ( prime factorisation  product)
2145 = 11×13×15
the three consecutive odd numbers whose product is 2145 are : 11 , 13 ,15

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!