Find all sets of three consecutive odd integers whose sum is between 20 and 30

3 odd numbers sum between 20 & 30

 you get n +n+2+n+4 = between 20 & 30

3n+6 = between 20 & 30

subtract 6 from all 3 numbers you now have 3n = between 14 and 24

 divide all 3 by 3 to get n = between 14/3 and 8

14/3 = 4 2/3

 the only odd numbers between 4 2/3 and 8 are 5 & 7

 so you have 5 + (5+2) + (5+4) = 21

and 7 + (7+2) + (7+4) = 27

b and c

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~