Factor the expression completely. (if the expression is not factorable using integers, enter prime.)
ae + bf + af + be
i figured it
(a+b)(e+f)

First you have to put like terms together:
bf+af+be+ae
Now you factor the first two terms and then the two last terms:
f(b+a)+e(b+a)
Now you factor even further. By putting what is in parentheses by what is outside the parentheses:
(b+a)(f+e)
What you got is correct as mine is too. I hope this formula helps for future problems:
ax+bx+ac+bc=x(a+b)+c(a+b)
=(a+b)(x+c)

Where are the functions?

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%