The admission fee at a small fair is $1.50 for children and $4.00 for adults. on a certain day, 2200 people enter the fair and $5050 is collected. how many children and how many adults attended that day?

I would write systems of equations for this problem.

1.5x + 4y = 5050

x + y = 2200

From there solve the system of equations where x represents the number of children and y represent the number of adults.

x + y = 2200

x = 2200 - y

Plug "x" into the other system of equation.

1.5(2200-y) + 4y = 5050

3300 - 1.5y + 4y = 5050

2.5y = 1750

y = 700

Since you have the value for y, solve for x.

x + y = 2200

x + 700 = 2200

x = 1500

So, the solution is: 1500 children and 700 adults attended.

Just to check our answers:

1.5x + 4y = 5050

1.5(1500) + 4(700) = 5050

2250 + 2800 = 5050

5050 = 5050

Well in order to lose a pound you would have to burn 1,500 calories. the more calories you burn the more weight you lose. in order to lose 2 pounds you would have to run 4 hours and 28 minutes.

I’m not sure i’m sorry