Kathy lives directly east of the park. the football field is directly south of the park. the library sits on the line formed between kathy's home and the football field at the exact point where an altitude to the right triangle formed by her home, the park, and the football field could be drawn. the library is 9 miles from her home. the football field is 12 miles from the library.
a. how far is the library from the park?
b. how far is the park from the football field?

see the attached figure to better understand the problem

Let

z---------> distance from the library to the park in miles

x-------> distance from the park to the to the football field in miles

y-------> distance from the park to Kathy's home in miles

we know that

In the right triangle ABC

Applying the Pythagorean Theorem

-----> equation

In the right triangle ABD

Applying the Pythagorean Theorem

-----> equation

In the right triangle BCD

Applying the Pythagorean Theorem

-----> equation

Add equation and equation

-----> equation

Substitute equation in equation

Find the value of x

therefore

the answer is

Part a) The distance from the library to the park is equal to

Part b) The distance from the park to the to the football field is equal to

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation:

360/29

step-by-step explanation: