The sum of three numbers is 62. the second number is equal to the first number diminished by 4. the third number is four times the first. what are the numbers? which three expressions could be used to represent the numbers?

1st number = x

2nd number = x-4

 3rd number = 4x

now you have x + x-4 +4x = 62

combine like terms

6x-4 = 62

add 4 to each side

6x = 66

divide both sides by 6

x = 66/6 = 11

1st number = 11

 2nd number = 11-4 = 7

 3rd number = 4*11 = 44

11+7+44 = 62

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.