What is the range of the function f(x) = 3x2 + 6x – 8? {y|y ≥ –1} {y|y ≤ –1} {y|y ≥ –11} {y|y ≤ –11}

The range of the function f(x)=3x²+6x-8 is:

{y|y ≥ –11}

Step-by-step explanation:

The function f(x)=3x²+6x-8 could also be written as:

f(x)=3x²+6x+3-11

f(x)=3(x²+2x+1)-11

f(x)=3(x+1)²-11

as we know that the value of 3(x+1)²≥0

Then, the value of 3(x+1)²-11≥-11

i.e. f(x)≥-11

Hence, the range of the function f(x)=3x²+6x-8 is:

{y|y ≥ –11}

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step-by-step explanation:

step-by-step explanation:

sry but any answer choices