If the tangent line to y = f(x) at (5, 3) passes through the point (0, 2), find f(5) and f '(5)

Since we have (5,3), f(5)=3

f'(5) is the slope of the line at x=5

we are given that the line tangent to f(x) at x=5 passes through the point (0,2)

so find the slope of that line
we know it passes through (5,3) and (0,2)
slope between and is

slope between (5,3) and (0,2) is [/tex]\frac{3-2}{5-0}=\frac{1}{5}[/tex]

f(5)=3
f'(5)=

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5