Acar starts with a speed of 20km/ hr and accelerates at a rate of 3.4 m/s for 20 seconds. what is the final speed of the car in km/hr?

The relevant formula that we can use in this situation is:

v = v0 + at

where v is the final velocity, v0 is the initial velocity = 20 km/hr, a is acceleration at 3.4 m/s^2 and t is time at 20 seconds

First convert v0 to m/s, v0 = 5.56 m/s

v = 5.56 m/s + 3.4 m/s^2 * 20 s

v = 73.56 m/s

Then convert back to km/hr:

v = 264.82 km/hr

it is c, trust i got your back lol

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15