Which of the following is not a way to represent the solution of the inequality 3(2x − 1) greater than or equal to 4(2x − 3) − 3? (1 point) a) x less than or equal to 6 b) 6 greater than or equal to x c) a number line with a closed circle on 6 and shading to the left d)a number line with a closed circle on 6 and shading to the right

Option D). is the option.

Step-by-step explanation:

The given inequality is 3(2x - 1) ≥ 4(2x - 3) - 3

Now we will solve the inequality to get the answer.

3(2x -1) ≥ 4(2x - 3) - 3

6x - 3 ≥ 8x - 12 - 3 (distribution law)

6x -3 + 3 ≥ 8x - 12 - 3 + 3

6x ≥ 8x - 12

By adding 12 on both the sides

6x + 12 ≥ 8x -12 + 12

Now we will subtract 6x from both the sides

6x - 6x + 12 ≥ 8x -6x

12 ≥ 2x

2x/2 ≤ 12/2

x ≤ 6

So option D) A number line with a closed circle on 6 and shading to the right is incorrect. Rest all options are correct.

-5, your answer was correct

are you missing something?

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