![Standard\ form:f(x)=ax^2+bx+c\\--------------------\\f(x)=2(x-1)^2+3=2(x-1)(x-1)+3\\\\=2[(x)(x)+(x)(-1)+(-1)(x)+(-1)(-1)]+3\\\\=2(x^2-x-x+1)+3=2(x^2-2x+1)+3|use\ distributive\ property\\\\=2x^2-4x+2+3=\boxed{2x^2-4x+5}\\\\\boxed{f(x)=2x^2-4x+5}](/tpl/images/0257/4148/3d4a3.png)
Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form.
f(x) = 2x2 + 5
f(x) = 4x...
Mathematics, 24.09.2019 06:30 yaya111601
Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form.
f(x) = 2x2 + 5
f(x) = 4x2 − 8x + 7
f(x) = 2x2 + 4x + 5
f(x) = 2x2 − 4x + 5
Answers: 2
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