Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. they spent a total of $30 to buy a total of 22 packets of wafers of the two varieties.
part a: write a system of equations that can be solved to find the number of packets of strawberry wafers and the number of packets of chocolate wafers that devon and his friends bought at the carnival. define the variables used in the equations. (5 points)
part b: how many packets of chocolate wafers and strawberry wafers did they buy? explain how you got the answer and why you selected a particular method to get the answer. (5 points)

Let x = the strawberry wafers and y = the chocolate ones
x+y = 22   (the number of wafers they bought it 22)
3x + y = $30   (the cost of the $3 wafers and $1 wafers = $30)
 
if i add 8 to the first equation they will both be worth 30.   (x+y+8=30)
since they are now both equal to the same thing (30) i will set them equal to each other.
3x+y = x+y+8   now lets get the like terms on the same side by subtracting x from
                        3x and y from y
2x = 8   (notice the y's are gone since y -y =0)
divide both sides by 2 and get x= 4
so 4 packets of the $3 wafers.     and since x+y = 22   4 +? =22   (answer 18)
final answer: 4 packets of the $3 wafers and 18 packets of $1 wafers
check: let try it in our other equation   3x + y = $30 (remember x=4, y=18)
3(4) +18 = $30
12 + 18 = 30
        30   = 30

The answer is 26 to 1