For nitrogen to be a liquid, its temperature must be within 12.78 °f of –333.22 °f. the equation |x + 333.22 | = 12.78 can be used to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid.

for nitrogen to be a liquid, its temperature must be within 12.78 °f of –333.22 °f. which equation can be used to find the maximum and minimum temperatures at which nitrogen is a liquid, x?

the equation that can be used to find the maximum and minimum temperatures is

|x +   ⇒ 333.22| =   ⇒ 12.78.

-320.44 is the maximum temperature at which nitrogen is a liquid.

-346 is the minimum temperature at which nitrogen is a liquid.

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

i agree because i see the other persons thinking is clear