The magnitude, m, of an earthquake is defined to be m=log i/s, where i is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and s is the intensity of a “standard” earthquake, which is barely detectable. what is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? use a calculator. round your answer to the nearest tenth.

log(35) = 1.544

 rounded to nearest tenth = 1.5

The magnitude of the earthquake that is 35 times more intense than a standard earthquake=1.5

Step-by-step explanation:

Given : The magnitude M of an earthquake is defined to be  ---(1)

, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and

S is the intensity of a “standard” earthquake, which is barely detectable.

If  the magnitude of an earthquake that is 35 times more intense than a standard earthquake

⇒Intensity of earthquake I=35 S

Substitute the value of I in (1), we get

∴ The magnitude of the earthquake that is 35 times more intense than a standard earthquake=1.5

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.