If the least common multiple of 2 numbers is 60 and one number is 7 less then the other number what is the answer

Your question is not clear.  I must guess what you meant.  Did you mean "Find the two numbers?"

If so, let the two numbers be m and n.  Then mn=60 and m=n-7.

Then (n-7)(n) = 60, or n^2 -7n - 60 = 0.  This factors:  (n+5)(n-12) = 0 

Thus, n = -5 or n = 12.

check:  does mn = 60?  Does 12*5 = 60?  Yes.  Is m (which is 5)  7 less than n (which is 12)?  Yes.

Note that you could also check to see whether n=-5 and m=n-7=-5-7=-12 is also a solution.

The answer is 76° i believe

Hold on lemme do the work