Acompany manufactured a 16-oz box of cereal. boxes are randomly weighted to ensure the correct amount. if the discrepancy in weight is more than 0.15 oz, the production is stopped. what is the range of acceptable values for production to continue?

The acceptable range will be : 15.85 oz to 16.15 oz

Step-by-step explanation:

Let the weight of the box be = x

As given,

If the discrepancy in weight is more than 0.15 oz, the production is stopped.

And if the discrepancy in weight is less than 0.15 oz then the production will continue.

We can express this as : If ; the production continues

or we can say

Now, z = x-16, and a=0.15, then the value becomes,

Solving for x:

We get the final range as :

Therefore, the answer is :

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.