Ametronoe uses an invented pendulum rod to control tempo. a weight can be slid up the pendulum rod to decrease tempo, or down the pendulum rod to increase tempo. a second fixed weight is hidden inside the mettronome at the base of the pendulum. the longer the distance between the two weights, the slower the tempo. the equation is used to calculate the frequency of the metronome pendulum: f=square of g/l / 2x f= frequency (number of back and forth cyles in 1 second) measured in hertz g=the acceleration due to gravity; 9.8m/s^2 l=length of the rod- in this case, the length of the rid between the two weights- measured in meters. part 1 each time the metronome's pendulum completes one back and forth cycle, it produces two ticks or beats. to calibrate the metronome for beats per minute (bpm), the manufacturer needs to know the length of the pendulum for various tempos. solve f=square root of g/l /2x for l. part 2 if f=1.6 then there are 2 beats a second, or 192 beats per minute (bpm) what is the length of the rod between the two weights at that tempo? use you equation from part 1 to solve for l.