Arectangle has a perimeter of 60 inches and length of 22 what is the width of the rectangle

perimeter = 2l +2w

length = 22

perimeter = 60

 60 = 2(22) +2w

60 = 44 +2w

 subtract 44 from both sides

16 = 2w

w = 16/2

w = 8

 width is 8 inches

answer: i think the answer is etheir c or d but i don't know which one but have a good day!

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)