What are the roots of x in -10x^2 + 12x - 9=0

The "roots" of a function are the values of x for which y is zero. To solve this, be must use the quadratic formula, where a= -10, b=12, and c=-9
Quadratic formula:
x= [-b +/- √(b²-4ac)] ÷ 2a
Plugging in a, b, and c:
x= (-12 +/- √144 - 4(-10)(-9)) ÷ -20
 x= (-12 +/- √(144 + 360)) ÷ -20
x = (-12 +/- 6√14) ÷ -20
x  = (-12 + 6√14)/-20 or (-12 - 6√14)/ -20
x = 3/5 +/- 3√(14) / 10

Idon’t know what the answer is i wish i could