Answers: 2
![\bf \cfrac{8-7i}{1-2i}\cdot \cfrac{1+2i}{1+2i}\implies \cfrac{(8-7i)(1+2i)}{(1-2i)(1+2i)}\implies \cfrac{8+16i-7i+14i^2}{1^2-(2i)^2} \\\\\\ \cfrac{8+9i+14(-1)}{1-(2^2i^2)}\implies \cfrac{-6+9i}{1-[4(-1)]}\implies \cfrac{-6+9i}{5}\implies -\cfrac{6}{5}+\cfrac{9}{5}i](/tpl/images/0064/4201/e9471.png)
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Write the quotient in standard form: 8-7i/1-2i...
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