The three incoming currents at a node in an electrical circuit measure 0.7 amps, 0.68 amps, and 0.47 amps two of the three outgoing current measure 0.8 amps and 0.55 amps find the measure of the third outgoing current

What goes in goes out. This means none of the current is lost. So if 0.7amps+0.68amps+0.47amps = 1.85 amps comes in, then 1.85 amps goes out. So far we have 0.8 amps+0.55 amps going out= 1.35 amps. This means we need an additional 1.85-1.35amps going out= 0.5 amps for the third outgoing current. Cheers!