Mathematics, 08.07.2019 08:50 ninigilford

Does anyone know how to do 9 and 10

Answers: 2

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Answer from: ana1810

9.2x-9<7
add 9 to both sides, 2x<16
divide both sides by 2, x<8
A.

10.n<5
-4n+11>-9 Subtract 11 from both sides
-4n>-20 then, divide both sides by -4
In these greather than less than equations, when you divide a negative by another negative, you must flip the sign
so that would be, n<5
D

Answer from: pattydixon6

9) 2x - 9 < 7

Add 9 to both sides.

2x < 7 + 9

Simplify.

2x < 16

Divide both sides by 2.

x < 8

10) Go through each answer choice & check.

a) 4n + 11 > -9

Subtract 11 from both sides.

4n > -9 - 11

Simplify.

4n > -20

Divide both sides by 4.

n > -5

(a) is incorrect.

b) 4n + 11 < -9

Subtract 11 from both sides.

4n < -9 - 11

Simplify.

4n < -20

Divide both sides by 4.

n < 5

(b) is incorrect

c) -4n + 11 <-9

Subtract 11 from both sides.

-4n < -9 - 11

Simplify.

-4n < -20

Divide both sides by -4.

n > 5

(c) is incorrect

d) -4n + 11 > -9

Subtract 11 from both sides.

-4n > -9 - 11

Simplify.

-4n > -20

Divide both sides by -4.

n < 5

(d) is correct

~Hope I helped!~

Answer from: Quest

geometric series converge the common ratio r has magnitude less than one.

$|r| < 1$

which is equivalent to

$-1 < r < 1$

for the example we need

|2-x| < 1

-1 < 2-x and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1 diverges

1b. r=50/100=1/2 converges

when these converge they converge to

$s = \dfrac{a}{1 -r}$

where a is the first term.

$s = \dfrac{100}{1 - 1/2} = 200$

answer: 200

1c. r=-1 so it's not the case that |r| < 1. diverges

2a. x is the common ratio so we converge when |x|< 1

2b. r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c. r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

$|x| < \frac 1 2 \sqrt[3]{2}$

Answer from: Quest

-6 is the correct option from the above given options

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