The fifth term of a geometric sequence is 781.25. each previous term is 1/5 of the value of the current term. which recursive formula represents the situation?

The required recursive function is an = 5an-1

Let the general formula for the recursive function be expressed as:

where

If the fifth term is 781.25, hence a5 = 781.25

If the previous term is 1/5 of the value of the current term.

Hence R = 5

Substitute the given values into the formula:

781.25 = 5an-1

Hence the required recursive function is an = 5an-1

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Step-by-step explanation:

Given fifth term of a geometric sequence is 781.25.

.

Also, each previous term is 1/5 of the value of the current term.

Therefore, common ratio would be 5.

But we just need to find the recursive formula .

Recursive formula of a geometric sequence is given by

Plugging value of r in above formula, we get

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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