The width of a rectangle is 8 inches shorter than its length. the perimeter of the rectangle is 18 square cm. what are the length and width? which equation models this problem? a. 8 x l = 18 - 8 b. l(l - 8) = 18 c. l + (8 + 2l) = 18 d. 2l + 2 (l - 8) = 18

Option D. 2[L + ( L-8)] = 18

Step-by-step explanation:

Let the length of rectangle is L and width is W

The width of a rectangle is 8 meters shorter than its length

Then equation will be W = L - 8 (1)

The perimeter of the rectangle is 18 cm

Then P = 18 cm = 2 ( l + w )

2(l + w) = 18 (2)

Now we substitute the value of W from equation (1) to equation (2)

2[L + ( L-8)] = 18

Option D. is the answer.

50- 250 is correct i did that one too

step-by-step explanation:

6/20

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