Line segments hg and hj in xy-coordinate plane both have common endpoint h (-2, 4) and midpoints m1 at (-2, 10) and m2 (8, 5), respectively. what is the distance between m1 and m2? round to the nearest tenth. a. 11.1 b. 11.2 c. 15 d. 18.0

Distance formula : sqrt ((x2 - x1)^2 + (y2 - y1)^2)
(-2,10)x1 = -2 and y1 = 10
(8,5)x2 = 8 and y2 = 5
now we sub
d = sqrt ((8 - (-2)^2 + (5 - 10)^2)
d = sqrt ((8 + 2)^2 + (-5^2))
d = sqrt (10^2) + (-5^2)
d = sqrt (100 + 25)
d = sqrt 125
d = 11.18 which equals 11.2 when rounded to the nearest tenths <=

Y=-3x is the correct answer