The number of miles on car a is 50 more miles than the number of miles on car b and the number of miles on car b is 30 more miles more than the number of miles on car c all the cars travel 50 miles in 1 hour after 1 hour twice the number of miles no car a is 70 miles les than 3 times the number of miles of miles on car c how many miles were there on car b initially

Let's write down what we know:

a=50+b

b=30+c

After one hour:

(a+50)*2=-70+3*(c+50)

let's eliminate the brackets:

2a+100=-70+3c+150
2a+100=+3c+80
which is:

2a=-20+3c
substituting from a=50+b:

100+2b=-20+3c

substituting from b=30+c

100+2(30+c)=-20+3c

100+60+2c=-20+3c

160+20=3c-2c

180=c.

So we know that c is equal to 40, then b will be b=30+c

b=30+180=210.

So B had 210 miles initially.

The answer is 1 because you have to flip the sign when dividing by negative number and 3