box has 1 red marble, 3 blue marbles, and 4 green marbles. maya draws a blue marble randomly from the box, replaces it, and then draws another marble randomly. what is the probability of drawing 2 blue marbles in a row?

9/64

Step-by-step explanation

We can add together all of the marble types to get a total of 1 + 3 + 4 = 8. Both draws will have the same probability since the marbles are being replaced and they are both blue marbles. The probability on either draw independently will be 3/8. The combined probability will be 3/8 * 3/8 = 9/64

9/64

Step-by-step explanation: All the marbles together are 8 and there 3 blue marbles so 3/8 is the probability but not the probability of two so that times two is 3/8 × 3/8 = 9/64 :)

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

step-by-step explanation:

where is the questions